# NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.5

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12 ## NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.5

NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.5

Exercise 14.5

Ex 14.5 Class 6 Maths Question 1.
Draw AB of length 7.3 cm and find its axis of symmetry.
Solution:
Step I: Draw (overline { AB }) = 7.3 cm Step II: Taking A and B as centre and radius more than half of (overline { AB }), draw two arcs which intersect each other at C and D.
Step III: Join C and D to intersect (overline { AB }) at E. Thus, CD is the perpendicular bisector or axis of symmetry of (overline { AB }).

Ex 14.5 Class 6 Maths Question 2.
Draw a line segment of length 9.5 cm and construct its perpendicular bisector.
Solution:
Step I: Draw a line segment (overline { PQ }) =9.5 cm Step II: With centres P and Q and radius more than half of PQ, draw two arcs which meet each other at R and S.
Step III: Join R and S to meet (overline { PQ }) at T.
Thus, RS is the perpendicular bisector of PQ.

Ex 14.5 Class 6 Maths Question 3.
Draw the perpendicular bisector of (overline { XY }) whose length is 10.3 cm.
(a) Take any point P on the bisector drawn. Examine whether PX = PY.
(b) If M is the midpoint of (overline { XY }) . What can you say about the length of MX and MY?
Solution:
Step I: Draw a line segment (overline { XY }) = 10.3 cm. Step II : With centre X and Y and radius more than half of XY, draw two arcs which meet each other at U and V.
Step III: Join U and V which meets (overline { XY }) at M.
Step IV: Take a point P on (overline { UV }) .
(a) On measuring, PX = PY = 5.6 cm.
(b) On measuring, (overline { MX }) = (overline { MY }) = (frac { 1 }{ 2 }) XY = 5.15 cm.

Ex 14.5 Class 6 Maths Question 4.
Draw a line segment of length 12.8 cm. Using compasses, divide it into four equal parts. Verify by actual measurement.
Solution:
Step I: Draw a line segment (overline { AB }) = 12.8 cm Step II : With centre A and B and radius more than half of AB, draw two arcs which meet each other at D and E.
Step III : Join D and E which meets (overline { AB }) at C which is the midpoint of (overline { AB }).
Step IV : With centre A and C and radius more than half of AC, draw two arcs which meet each other at F and G.
Step V: Join F and G which meets (overline { AC }) at H which is the midpoint of (overline { AC }) .
Step VI : With centre C and B and radius more than half of CB, draw two arcs which meet each other at J and K.
Step VII : Join J and K which meets (overline { CB }) at L which is the midpoint of (overline { CB }) .
Thus, on measuring, we find
(overline { AH }) = (overline { HC }) = (overline { CL }) = (overline { LB }) = 3.2 cm.

Ex 14.5 Class 6 Maths Question 5.
With (overline { PQ }) of length 6.1 cm as diameter, draw a circle.
Solution:
Step I: Draw (overline { PQ }) = 6.1 cm
Step II: Draw a perpendicular bisector of (overline { PQ }) which meets (overline { PQ }) at R i.e. R is the midpoint of (overline { PQ }). Step III : With centre R and radius equal to (overline { RP }) , draw a circle passing through P and Q.
Thus, the circle with diameter (overline { PQ }) = 6.1 cm is the required circle.

Ex 14.5 Class 6 Maths Question 6.
Draw a circle with centre C and radius 3.4 cm. Draw any chord (overline { AB }) . Construct the perpendicular bisector of (overline { AB }) and examine if it passes through C.
Solution:
Step I: Draw a circle with centre C and radius 3.4 cm.
Step II: Draw any chord (overline { AB }).
Step III : Draw the perpendicular bisector of (overline { AB }) which passes through the centre C. Ex 14.5 Class 6 Maths Question 7.
Repeat Question number 6, if (overline { AB }) happens to be a diameter.
Solution:
Step I: Draw a circle with centre C and radius 3.4 cm.
Step II : Draw a diameter AB of the circle. Step III : Draw a perpendicular bisector of AB which passes through the centre C and on measuring, we find that C is the midpoint of (overline { AB }) .

Ex 14.5 Class 6 Maths Question 8.
Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?
Solution:
Step I: Draw a circle with centre 0 and radius 4 cm. Step II: Draw any two chords (overline { AB }) and (overline { CD }) of the circle.
Step III : Draw the perpendicular bisectors of (overline { AB }) and (overline { CD }) i.e. I and m.
Step IV : On producing the two perpendicular bisectors meet each other at the centre O of the circle.

Ex 14.5 Class 6 Maths Question 9.
Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of (overline { OA }) and (overline { OB }) . Let them meet at P. Is PA = PB?
Solution:
Step I: Draw an angle XOY with O as its vertex.
Step II : Take any point A on OY and B on OX, such that OA + OB. Step III : Draw the perpendicular bisectors of OA and OB which meet each other at a point P.
Step IV : Measure the lengths of (overline { PA }) and (overline { PB }). Yes, (overline { PA }) = (overline { PB }).                      